Why is an #11 playing an #11?

BeantownKnight

All-Conference
Feb 14, 2008
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I don't know too much about how all of this works but I don't imagine that MSU (#11) playing UCLA (#11) is a normal thing, right? Why is this happening?
 

jordkap

All-Conference
Jul 11, 2016
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The last 4 teams into the field have to play an extra game. Whoever wins is slotted into the 11 seed, thus they technically all are 11s
 

ecojew

All-Conference
Feb 1, 2006
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Hasn't it been two 12-12 matchups some years? It might depend upon the relative strength of the lowest at-large teams compared to the conference champs of the better one-bid conferences.
 

herdof3

All-Conference
Sep 27, 2006
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4 extra teams from 64. 4 extra games. last 4 autobids play in as 16 seeds and last 4 at large bid teams (typically 11 - 12) play in. after that you are down to 64 for the regular tournament.
 

Sideline20

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Jul 27, 2001
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I think the play ins are normally 12's but since the Ivy League did not play and had an autobid there were more at large teams therefore the last at large teams were 11's.
 

BeantownKnight

All-Conference
Feb 14, 2008
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Oh. I thought the play-in games were (always) slotted as #16. They have those games where the teams play for the opportunity to get squashed by a #1.
 

Sideline20

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Jul 27, 2001
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There were always 2 16 vs 16 games to face 1's and 2 12 vs 12 teams to face the 12's that didn't have a play in game.